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\[sin^2 \theta = 1\] Find general solution of \(\theta\). I solved for sin \(\theta\) = \(\pm\)1 and got \(\theta = n\pi + (-1)^n \cfrac{\pi}{2}\) or \(\theta = n\pi + (-1)^n \cfrac{3\pi}{2}\) How to find combined solution
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sometimes....i doubt you're really in high school.....
Why ?
that kind of trigonometry is rarely taught in high school...
...or maybe i just don't know what that is...
That is general solution to trigonometric equation
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@estudier @experimentX
why dont you treat it like this: 1 = sin^2 @ or cos^2 @ = 0 easier ?
then I have cos\(\theta\) = 2n\(\pi\) \(\pm\) \(\cfrac{\pi}{2}\)
you mean @ = that,, yep//
Yes
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