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Biology 13 Online
OpenStudy (anonymous):

This pedigree chart tracks the inheritance of a recessive trait that is not sex-linked. Based on the information in the chart, which of the following statements is true? Individual #8 must be heterozygous for the trait. Individual #10 must be heterozygous for the trait. Individual #13 must be homozygous dominant. Individual #3 must be homozygous dominant.

OpenStudy (anonymous):

OpenStudy (anonymous):

OK we will do it together

OpenStudy (anonymous):

kk

OpenStudy (anonymous):

First of all to find it you must find the genotype for Individual #1 and 2

OpenStudy (anonymous):

k

OpenStudy (anonymous):

I was thinking its A...

OpenStudy (anonymous):

For individual 1 checkout the key which shows that he is a male who carries a recessive trait right?

OpenStudy (anonymous):

yes its a male with a recessive trait

OpenStudy (anonymous):

Lets take B for dominant and b for recessive

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

So the genotype for individual 1 is (bb) because he has a recessive trait.

OpenStudy (anonymous):

yea

OpenStudy (anonymous):

OK what is the trait for individual 2?

OpenStudy (anonymous):

female dominante

OpenStudy (anonymous):

spelled dominant wrong :l

OpenStudy (anonymous):

So here you have two genotypes which can be dominant which are (BB) and (Bb)

OpenStudy (anonymous):

after this I have 1 more then I'm all good for the rest :)

OpenStudy (anonymous):

yea

OpenStudy (anonymous):

OK to know what is the correct genotype for individual 2 by looking at their children which are individuals 5,6,7 and 8

OpenStudy (anonymous):

all dominant traits for 1

OpenStudy (anonymous):

all dominant traits for 5 6 7 and 8*

OpenStudy (anonymous):

So is the genotype for individual (BB) or (Bb)

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

So is it (BB) or (Bb)??

OpenStudy (anonymous):

BB

OpenStudy (anonymous):

No its (Bb)

OpenStudy (anonymous):

on the phone...

OpenStudy (anonymous):

Try using the Punnet Square between Individual 1 and 2 Individual 1: bb Individual 2: BB or Bb Ok so try crossing bb with BB and cross bb with Bb

OpenStudy (anonymous):

k

OpenStudy (anonymous):

Bb, Bb, BB, bB

OpenStudy (anonymous):

This is you crossed bb with BB right?

OpenStudy (anonymous):

I'm confused... and yes

OpenStudy (anonymous):

So cross bb with Bb and then you will relise that you will get Bb,Bb,Bb and Bb.

OpenStudy (anonymous):

NOO sorry

OpenStudy (anonymous):

Its my mistake

OpenStudy (anonymous):

Its BB and not Bb

OpenStudy (anonymous):

ok gotcha

OpenStudy (anonymous):

Ok so if you cross bb with BB you will get Bb,Bb,Bb and Bb which are all dominant. Unlike crossing bb with Bb which will give you Bb,bb,Bb and bb which are half dominant and half recessive right?

OpenStudy (anonymous):

yea

OpenStudy (anonymous):

hey i gtg in a couple min... were almost there right?

OpenStudy (anonymous):

right

OpenStudy (anonymous):

alright lets finish this then

OpenStudy (anonymous):

OK its written that individual 8 must have a hetrozygous trait true or false?

OpenStudy (anonymous):

true

OpenStudy (anonymous):

Luckily we found the answer which is the first one since its only asking for statement to be correct and we found it.

OpenStudy (anonymous):

alright thanks :)

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