Identify the vertex and the axis of symmetry of the graph of the function y = 3(x + 2)2 – 3.
vertex: (2, –3); axis of symmetry: x = 2
vertex: (–2, –3); axis of symmetry: x = –2
vertex: (2, 3); axis of symmetry: x = 2
vertex: (–2, 3); axis of symmetry: x = –2
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OpenStudy (anonymous):
this is a vertex form :
y=a(x-h)^2 +k
with vertex (h,k)
OpenStudy (anonymous):
hence the axis of symmetry is x =h
OpenStudy (anonymous):
can you answer now?
OpenStudy (anonymous):
I dont understand how to write it ?
OpenStudy (anonymous):
general form :
y=a(x-h)^2 +k
our case :
y = 3(x + 2)2 – 3
so for us
a = 3
h = -2
k = -3
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OpenStudy (anonymous):
is the vertex ( 2, -3 )
OpenStudy (anonymous):
try again using what i just wrote
OpenStudy (anonymous):
I dont understand what x is ?
OpenStudy (anonymous):
x is the independent variable ..
given
y=a(x-h)^2 +k
the vertex is (h,k) and axis of symmetry is x =h
OpenStudy (anonymous):
sorry my internet connection is bad
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