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If b > 0, how can we write a number a as a logarithm in base b?
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\(a = \log_b b^a\)
if thats what u looking for
okay, but why?
you familiar with inverse functions ?
yes
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exponent and log are inverses of each other
u send 'a' to exponent u take log of above result u get ur 'a' back
\(f(x) = b^x\) \(g(x) = \log x\) if g is the inverse of f, g(f(x)) = x
g(f(a)) = a
g(b^a) = a
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okay, thank you
log_b b^a = a wlcme :)
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