Question

Standard form for a parabola with this equation! Help please!

Answer 1

\[y = -\frac{ 1 }{ 4 }x^{2} -x + \frac{ 1 }{ 4 } \]

Answer 2

I don't get the completing the square part

Answer 3

drawing? can't see equation

Answer 4

that equation is in standard form, u need to get it in vertex form ?

Answer 5

yes

Answer 6

-1/4(x^2+4x)+1/4
what to add and subtract ?

Answer 7

subtract 1/4

Answer 8

we add and subtract the square of half of co-efficient of x
so here, what is half of 4 ?

Answer 9

2

Answer 10

and its square ?

Answer 11

4

Answer 12

so what will u add and subtract ?

Answer 13

Do you subtract the square?

Answer 14

u add and subtract the 4
like this:
-1/4(x^2+4x+4 -4)+1/4
can u go ahead ?

Answer 15

y-1/4 +4 = -1/4(x^2+4x -4)

Answer 16

y-1/4 -4(1/4) = -1/4(x^2+4x +4)

Answer 17

why -4(1/4) on the left???

Answer 18

y=-1/4(x^2+4x+4 -4)+1/4
= -1/4 (x^2+4x+4) -1/4 (-4) +1/4
y-1/4 -1/4(4) = -1/4(x^2+4x+4)
confusing ?

Answer 19

why did you not add it to both sides? why subtract? it says -1/4(-4)

Answer 20

Ohh I see it now

Answer 21

Wow thank you so much

Answer 22

u can continue to get the vertex form, right ?

Answer 23

yess
It is quite easy now. Thank you so much :) I can sleep now haha

Answer 24

welcome ^_^