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Mathematics 6 Online
OpenStudy (anonymous):

15c^2-7cd-2d^2

OpenStudy (calculusfunctions):

\[15c ^{2}-7cd -2d ^{2}\]You want to factor this expression correct?

OpenStudy (anonymous):

yes

OpenStudy (calculusfunctions):

So do you need help with factoring in general or just this particular question?

OpenStudy (anonymous):

when there is two variables i get stuck... do i have to the factor of seven which adds to two?

OpenStudy (calculusfunctions):

Factoring with two variables is no different, except each binomial factor now also enads with a variable. Example: Factor the following i). x² - 2x -8 = (x - 4)(x + 2) ii). x² - 2xy - 8y² = (x - 4y)(x + 2y) Do you see?

OpenStudy (calculusfunctions):

*ends

OpenStudy (calculusfunctions):

Now you do your question and if you want, I will check it.

OpenStudy (anonymous):

what do i do with "15"? im stuck ok so (15c-?d)(c+?d) ?????

OpenStudy (calculusfunctions):

Example: Factor 3x² - 2xy - 5y² Step 1: Find two integers with a product of (3)(-5) or -15 and a sum of -2. The two integers would be +3 and -5. Decomposition method: (decompose the middle term in terms of the two integers) 3x² + 3xy - 5xy - 5y² (now group and factor the first two terms and then the last two) = 3x(x + y) - 5y(x + y) (now we have x + y as a common factor) = (x + y)(3x - 5y) Do you understand? If you want I can also teach you other methods besides decomposition.

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