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It's sigma notation
\[\sum_{k=3}^{7}\frac{ k+1 }{ k }=\frac{ 3+1 }{ 3 }+\frac{ 4+1 }{ 4 }+\frac{ 5+1 }{ 5 }+\frac{ 6+1 }{ 6 }+\frac{ 7+1 }{ 7 }\]w/c is the expanded form. To find the sum add up the right hand side expressions.
ok
3653/140?
and the sum is 26.09?
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I don't think that is the answer.
ok
It is 6.0928..
numerator is wrong, this is what i get http://www.wolframalpha.com/input/?i=%5Cfrac {+3%2B1+}{+3+}%2B%5Cfrac{+4%2B1+}{+4+}%2B%5Cfrac{+5%2B1+}{+5+}%2B%5Cfrac{+6%2B1
or 853/140?
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yeah that one
I had one last qeustion
On writing the expanded form on this sigma http://i729.photobucket.com/albums/ww292/akatushi101/img5.gif
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