Ask your own question, for FREE!
Mathematics 9 Online
OpenStudy (anonymous):

sqrt(x)+sqrt(1)=0

OpenStudy (anonymous):

unlikely since both terms on the left are positive

OpenStudy (anonymous):

I am doing implicit differentiation

OpenStudy (anonymous):

but you wrote \[\sqrt{x}+\sqrt{1}=0\] perhaps you meant \[\sqrt{x}+\sqrt{y}=0\]?

OpenStudy (anonymous):

which is just the point \((0,0)\) so my guess is the original question is something different

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

\[\sqrt{x}+\sqrt{y}=1\]

OpenStudy (anonymous):

oooh ok

OpenStudy (anonymous):

what did you get as a first step?

OpenStudy (anonymous):

|dw:1350520140644:dw|

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!