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usa the chain rule to find the derivative of h(x)=sin2xcos2x
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chain rule is like a cake, it has layers
wellll i really need to learn how to make this cake. because its confusing to me.
So like one of the previous ones sandy, we have the product rule. You can eliminate the need for product rule if you remember your double angle formula for sine though! :)
so for the product rule would u be sin2x and v would be cos2x?
Mhm :3
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sooo i got sin2x(-2sin(2x))+cos2x(2cos(2x)) ? haha i feel like i did that wrong...
Hmmm let's see :)
|dw:1350527438068:dw| Oh, looks like you did it correctly! :) I just got confused because you do it in the reverse order that I usually do hehe
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