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Mathematics 7 Online
OpenStudy (anonymous):

usa the chain rule to find the derivative of h(x)=sin2xcos2x

OpenStudy (anonymous):

chain rule is like a cake, it has layers

OpenStudy (anonymous):

wellll i really need to learn how to make this cake. because its confusing to me.

zepdrix (zepdrix):

So like one of the previous ones sandy, we have the product rule. You can eliminate the need for product rule if you remember your double angle formula for sine though! :)

OpenStudy (anonymous):

so for the product rule would u be sin2x and v would be cos2x?

zepdrix (zepdrix):

Mhm :3

OpenStudy (anonymous):

sooo i got sin2x(-2sin(2x))+cos2x(2cos(2x)) ? haha i feel like i did that wrong...

zepdrix (zepdrix):

Hmmm let's see :)

zepdrix (zepdrix):

|dw:1350527438068:dw| Oh, looks like you did it correctly! :) I just got confused because you do it in the reverse order that I usually do hehe

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