Draw the exponential which passes through the points (−1, 8) and (3, 3) . From your graph, estimate the halving time from your graph. Find an explicit formula, of the form f(x) = Aa^x for the exponential and calculate the halving time exactly from this formula.
\[f(x)= A \alpha ^{x}\]
all that is needed are the values for A and \(\large \alpha \), so find them: using (3, 3): \(\large 3=A \cdot \alpha ^{3} \) using (-1, 8): \(\large 8=A \cdot \alpha^{-1} \) solve this system of equations... can you do that?
I am not sure how to proceed.
solve for A in the first equation: \(\large 3=A \cdot \alpha^{3} \rightarrow A=\frac{3}{\alpha^3} \) plug this expression into the second equation... can you do the substitution from here?
Still confused by the exponent being divided into alpha^3, what happens here?
substitute this into the second equation: \(\large 8 = (\frac{3}{\alpha^3})\cdot \alpha^{-1} \) \(\large 8 = (\frac{3}{\alpha^3})\cdot \frac{1}{\alpha} \) \(\large 8 = \frac{3}{\alpha^4} \) \(\large \alpha^4 = \frac{3}{8}\rightarrow \alpha=\sqrt[4]{\frac{3}{8}} \) now that you've found alpha plug this in to the expression to find A.
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