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Mathematics 10 Online
OpenStudy (anonymous):

An object is thrown straight down from the top of a 220-foot building with an initial velocity of 26 feet per second. What is the velocity at 1 second?

OpenStudy (anonymous):

i think this belongs to physic department ? o_O

OpenStudy (anonymous):

Well, it's part of my calculus homework.

OpenStudy (anonymous):

Never mind, I got it.

OpenStudy (anonymous):

can i know how ? :D

OpenStudy (anonymous):

Write the position equation first, which is s(t)=-16t^2-26t+220

OpenStudy (anonymous):

Then find the derivative of it which is -32t-26

OpenStudy (anonymous):

plug in 1 for t into that equation and you get the velocity.

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