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|6x-7| = 6- |x-3| since it's in abs value, would it be -7-3 or 7+3? <-- when I add over |x-3|
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7+3 as absolute value do not take the minus sign
so I would end up with 7x+10=6 instead of 7x-10=6?
isn't it supposed to be 6x - 7 + x - 3 = -6?
that's what i was thinking too
where did the -6 come from?
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you make the right side negative
to make the absolute value disappear*
!!
so sorry i made it worse >.<"
what... how did you get -6? don't I just add -|x+3| over?
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yes |6x - 7| + |x-3| = 6 then, to make the absolute values disappear, you multiply the right side by -1
i understand now
i assume you're not familiar with that method @lookitswill ?
no i'm not
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