Question

please hlp me out

Answer 1

24. As the Aluminum rod and Copper rod joined are in parallel
t
Q
=
1 Al t Cu
Q
t
Q



   


 


l
KA( 1 2 )   
=
l
K A( )
l
K1A( 1 2 ) 2 1 2   

  
 K = K1 + K2 = (390 + 200) = 590
t
Q
=
l
KA( 1 2 )   
=
1
590 1104  (60  20)
= 590 × 10–4 × 40 = 2.36 Watt