Question

Help. Solve (3/x^2 + 3x) + (x+2/x+3) < (1/x)
Show me how to figure it out. :)

Answer 1

subtract \(\frac{1}{x}\) from both sides
add the terms
then check to see where the resulting fraction is negative

Answer 2

\[\frac{3}{x^2+3x}+\frac{x+2}{x+3}-\frac{1}{x}<0\]
\[\frac{x+1}{x+3}<0\] etc

Answer 3

Thanks

Answer 4

yw