Question

How do you find all real solutions for?
4x^4+16x^2+4=0

Answer 1

This is a quadratic equation in \(x^2\). So just substitute this into your equation:\[y=x^2\]and solve for y. Then solve for x using \(x=\pm\sqrt{y}\)

Answer 2

No real roots.

4x^4 is always at least zero, as is 16x^2.
Four is always at least four, so the sum of the three terms is always at least four.

Answer 3

so this would be no solution?

Answer 4

Correct. Do you understand what I said?

Answer 5

if you work out the discriminant of the quadratic then you will also see that it has no real solutions

Answer 6

okay thank you

Answer 7

yw :)

Answer 8

Do math every day.

Answer 9

i do... in school lol