Question

If k is a real number, what is the value of k if the following equation only has 1 solution?
kx^2+36x+k=0

Answer 1

It will help to divide the equation by "k" and complete the square.

Answer 2

how would you complete the square?

Answer 3

no need

Answer 4

just check wether

b^2-4ac =0

Answer 5

a=k, b=36, and c=k

Answer 6

(36)^2-4k^2=0
k^2=9^2
k=9

Answer 7

sorry k=18

Answer 8

or k=-18

Answer 9

sorry, i just dont follow-what do you do after 36^2-4k^2?

Answer 10

oh ok

Answer 11

36^2-4k^2=0
4k^2=36^2
k^2=(36^2)/(4)
take the square root on both sides
|k|=36/2=18

Then,

k=+18 or k=-18

Answer 12

Oh! I get it now. thank you so much!