Find the point on the terminal side of θ = -3pi/4 that has an x coordinate of -1. Show your work for full credit.
id start with drawing a circle about the origin and marking the angle in it
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then its just a matter of determining the "height" of the triangle usiing basic trig functions
I have to explain it in words Im not sure how I would say it @amistre64 help with the wording?
me no goodest with splaining in words :/
the three posts i gave is prolly the best i can do with using words ... good luck tho
Well can you help me take a guess So can I say for the equation θ = -3pi/4 the poing that has a an x coordinate of -1 would be 1/4 ? @amistre64
no, the point would be defined as (-1,y) saying: the point that has a an x coordinate of -1 would be 1/4 is meaningless. the reference angle we have is pi/4 the tangent of that angle equals y/x, tan(a) = y/x solving for y gets us: x tan(a) = y , and since the angle ends up in the 3rd quadrant we will have a negative x and a negative y
Thank you @amistre64
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