Question

\[A\vee(\neg A\wedge B)\]

Answer 1

Truth table?

Answer 2

i know the answer , i wanna see you do it

Answer 3

So truth table right?

Answer 4

A B A V (~A ^ B)
1 1 1
0 1 1
0 0 0
0 1 1

Answer 5

@UnkleRhaukus

Answer 6

were are the intermediate columns?

Answer 7

Never heard of that term. Would you please explain? Thanks! :)

Answer 8

i cannot see how you got your third column

Answer 9

or your second or first for that matter
\

Answer 10

That was your question...

Answer 11

absorption

Answer 12

Oh and

1 0 1

I posted A - 0, B - 1 twice.

Answer 13

@ParthKohli he wants you to show ~A, ~A ^ B as intermediates

Answer 14

where did the numbers come form/?

Answer 15

Sorry, I thought you needed a truth table.

Answer 16

not really

Answer 17

I've never heard of that...sorry.

Answer 18

this is not ment to be a difficult question

Answer 19

Very Easy Question :)

Answer 20

I've not heard what an "intermediate" is.

Answer 21

He does want a truth table; @UnkleRhaukus the 0, 1 are false, true in boolean algebra.

Answer 22

@ParthKohli the intermediates are the inner steps i.e. ~A and then ~A ^ B before A V (~A ^ B)

Answer 23

Oh something like this?\[\rm A \vee (\neg A \wedge B) \equiv A\vee B\]

Answer 24

Oh that?

Answer 25

you havent justified it

Answer 26

OK, then wait a second.

Answer 27

A B ~A ~A ^ B A V (~A ^ B)
1 1 0 0 1
1 0 0 0 1
0 1 1 1 1
0 0 1 0 0

Answer 28

A B ~A ~A^B Av[~A^B]
T T F F T
T F F F T
F T T T T
F F T F F

Answer 29

Comparing truth tables,

A B A V (~A ^ B) A V B
1 1 1 1
1 0 1 1
0 1 1 1
0 0 0 0

So,\[\rm A \vee (\neg A\wedge B)\equiv A\vee B \]

Answer 30

@UnkleGenius Good enough?

Answer 31

thats the one