At a carnival game, a large horizontal board has holes of the same size cut in it. For the game, you toss a ball onto the board and it lands or rolls into one of the holes. The board is surrounded on all sides, so the ball is certain to fall in a hole. Three of the holes will earn a small prize and one of the holes will earn a large prize. If Grady buys a ticket for one ball that he'll toss on the board, what is the probability that he'll win a prize? Wouldn't the answer be 5%? (Please explain in steps even if it's right or wrong)
How many holes are there? 4? 3 hole with small prizes and 1 with large prizes ?
20 sorry.
XD no the anwser will not be 5%
it tells you that there are 4 holes with prizes
The possible answers are 5%, 15%, 20% and 40%
3 holes = small prize 1 hole = large prize
the question is asking for the possiblity that he will get a prize whether small or large
since there is 4 holes with prizes out of 20 holes
it would be 4/20 which equals...
So what do I do.. to solve is there a formula? Like P(event)=number of favorable outcomes/number of total outcomes..? IM SO CONFUSED D:
no. no formulas involved it is a logic and probability question
So what do I do? How did you get that fraction?
the question askes for the probability of grady getting a prize since there is 3 holes for small prizes and 1 hole for a large prize there is a total of 4 prize holes out of 20 there fore the fraction you get is 4/20
and 4/20 equals....
.2 x 100 = 20%
So you total them all and then make a fraction?... I get it now :D
XD yeah basically
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