Question

A solid gold cube with edge of 2" is melted down and recast as a cone with a 3" radius base.
Find the height of the cone.

Answer 1

\[V_{\text{cube}}=s^3\]\[V_{\text{pyramid}}=\frac{bh}3\]a cone is a pyramid with a circular base\[b_{\text{cone}}=\pi r^2\]
\[V_{\text{Au}}=V_{\text{cube}}=V_{\text{cone}}\]

Answer 2

can you see what to do?

Answer 3

erm i dunno 6.9 duuurrr halp

Answer 4

first plug in the side length of the cube into V_cube find the volume,

Answer 5

then solve the volume of the cone for h

Answer 6

and substitute in the radius r

Answer 7

and then the answer is what?

Answer 8

i hav't worked it out, that is your job

Answer 9

haven't*

Answer 10

\[v_{cube}=v_{cone}\]
\[s^{3}= \frac{ 1 }{ 3 }{\pi}r^{2}h\]
\[2^{3}=\frac{ 1 }{ 3 }{\pi}3^{2}h\]
\[h=\frac{ 8 }{ 3\pi }\]

Answer 11

thank you