Question

\[z^2+\frac12=0\]

Answer 1

Ohh! root of -1/2. :)

Answer 2

Won't it be like this. @UnkleRhaukus \[z = -1\sqrt{\frac{1}{2}}\]

Answer 3

i think the roots will be complex as -1 is coming in under root
\[\sqrt{-1} = i\]
\[z= \pm \sqrt{\frac{ 1 }{ 2 }} \times \sqrt{-1}\]
so just replace with i.. you will get your 2 roots.