Mathematics
6 Online
OpenStudy (anonymous):
[4.06]What is the equation of the line that passes through the points (−1, 3) and (1, 11)?
4x − y = 1
4x + y = 1
x − 4y = −13
4x − y = −7
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OpenStudy (anonymous):
@Algebraic! @robtobey @SheldonEinstein @Solmyr @dmezzullo @Faris_Waleed @mathteacher1729
Parth (parthkohli):
Point-slope form is classic.
Parth (parthkohli):
\[\rm y-y_1 = m(x - x_1)\]
OpenStudy (anonymous):
I found for the slope 4
OpenStudy (anonymous):
is that correct?
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Parth (parthkohli):
Yes!
OpenStudy (anonymous):
the point slope ofrm is y-11=4x(x-1)
OpenStudy (anonymous):
correct?
OpenStudy (anonymous):
sorry 4(x-1)
Parth (parthkohli):
\[\rm y - 11 = 4(x - 1)\]Yes!
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OpenStudy (anonymous):
yap correct
OpenStudy (anonymous):
then when i solve it gives me y=4x+7
OpenStudy (anonymous):
correct?
Parth (parthkohli):
Right!!
OpenStudy (anonymous):
then i have trouble can you walk me through it?
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Parth (parthkohli):
Yes, I will.
You have to get all variables on one side.
OpenStudy (anonymous):
how
OpenStudy (anonymous):
show me please?
Parth (parthkohli):
Subtract \(\rm 4x\) from both sides.
OpenStudy (anonymous):
so it gives me -4x-y=7
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OpenStudy (anonymous):
?
Parth (parthkohli):
No...\[\rm y = 4x + 7\]\[\rm y - 4x = 4x - 4x + 7\]
OpenStudy (anonymous):
these are my options for the answer
4x − y = 1
4x + y = 1
x − 4y = −13
4x − y = −7
Parth (parthkohli):
The options are wrong. ;)
Parth (parthkohli):
Or, if you need it, try plugging in values.
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OpenStudy (anonymous):
no the options are correct I assure you
Parth (parthkohli):
\[\rm 4(1) - 11 = 1 \]the first option is not right.
OpenStudy (anonymous):
may you just give me the answer?
Parth (parthkohli):
\[\rm 4(1) + 11 = 1\]not right either
Parth (parthkohli):
\[1 - 4(11) = -13\]no
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OpenStudy (anonymous):
is it the 4 one
Parth (parthkohli):
\[4 - 11 = -7\]
Parth (parthkohli):
Yes.
OpenStudy (anonymous):
thanks
OpenStudy (anonymous):
@ParthKohli can you help me with 2 others?
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Parth (parthkohli):
Sure, please post them in a new question... my computer is lagging.
OpenStudy (anonymous):
okay thanks