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Mathematics 17 Online
OpenStudy (anonymous):

.

OpenStudy (anonymous):

\[\sum_{k=1}^{4}(k-1)(k-2)\]

OpenStudy (anonymous):

Use Distributive Law to Remove the Bracket

OpenStudy (anonymous):

\[k^2-2k-k+2 = k^2-3k+2\] \[\sum_{k=1}^{4} k^2-3k+2\]

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

so that is the expanded form?

OpenStudy (anonymous):

because the sum has to equal to 8..

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