Solve the following system of equations. x - 2y = 6 2x - 4y = 10
At the first look, I knew what the solutions are.
Hint: Multiply first equation by 2.
what do u mean
Isolate either x or y from one of the equations and use this new definition on your variable in the other equation.
ok ?
Looks parallel, eh @Parth?
If you multiply equation one by 2 you get 2x-4y=12 2x-4y=10 Anything look funny about that?
x - 2y = 6 2x - 4y = 10 x=6+2y 2(6+2y)=10 x=6+2y 12+4y=10 x=6+2y 4y=-2 x=6+2y y=-1/2 x=7, x=-1/2
Double check your work @Kathi26 ...
@Kathi26 how do you think it ?
@CliffSedge can you solve it please ?
Sure, like I said above: "If you multiply equation one by 2 you get 2x-4y=12 2x-4y=10" Since 2x-4y=2x-4y, that implies that 12=10, which is false, so there is no solution. The lines are parallel.
nice thank you
Method two: x-2y=6 --> y=x/2-3 2x-4y=10 --> y=x/2-5/2 Both lines have the same slope but a different intercept, ergo, parallel, and no solution.
ok good luck bye
@nincompoop since the solution to a system of linear equations is where the lines intersect, might as well look at the graph of the lines.
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