Find the slope of the line that passes through the following points, (-2, 3) and (-1, -3)

Question

anonymous · Answer

$$gradient/slope=\frac{y2-y1}{x2-x1}$$
(-2,3) and (-1,-3)
(x1,y1)      (x2,y2)

now substitute those values into the formula, tell me what you get.

anonymous · Answer

-6/3 or -2

anonymous · Answer

$$M = \frac{y2-y1}{x2-x1} = \frac{-3-3}{-1-(-2)}=\frac{-6}{1}=-6$$

anonymous · Answer

you just need to be careful on the minus part.
x2 is -1   and x1 is -2
so when x2 - x1
              -1 - (-2) 
              -1 + 2 = 1

hero · Answer

y =   mx + b

 3 =  -2m + b
-3 = -1m + b

b = 3 + 2m
b = m - 3

b = b
3 + 2m = m - 3
2m - m = -3 - 3
        m = -6