find ther derivative of: f(x)=4/cotx + 6x^2
i have: -4/csc^2(x) + 12x
is that right?
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OpenStudy (anonymous):
4/cot x= 4 tanx
OpenStudy (anonymous):
and the derivative of 4 tanx = 4 sec^2 x
OpenStudy (anonymous):
do u know the derivative of 1/x?
OpenStudy (anonymous):
i meant sec not csc
OpenStudy (anonymous):
2 root x
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OpenStudy (anonymous):
or -x^2
OpenStudy (anonymous):
or somthing
OpenStudy (anonymous):
derivative of 1/x = -1/x^2
OpenStudy (anonymous):
but how did it come?
OpenStudy (anonymous):
okay but the derivative of cot = -csc2x
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OpenStudy (anonymous):
yes
OpenStudy (anonymous):
but u have to find the derivative of 4/cot x
OpenStudy (anonymous):
just wait...derivative of x is 1..right?
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
den will the derivative of 1/x be also 1?
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OpenStudy (anonymous):
no
OpenStudy (anonymous):
the derivative of 1/x = -1/x^2
OpenStudy (anonymous):
ok...so derivative of cot x is - cosec^2 x
den derivative of 1/cot x is - 1/ cosec^2x?
OpenStudy (anonymous):
r u getting..what do i mean?
OpenStudy (anonymous):
i know all my derivatives and my trig derivatives,
like i dont understand what you're trying to say here.
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OpenStudy (anonymous):
ok
OpenStudy (anonymous):
i just want to know why my answer isnt right and what the right answer is.
OpenStudy (anonymous):
right answer is 4 sec^2 x+12 x
OpenStudy (anonymous):
why
OpenStudy (anonymous):
yep confirmed askash123 is right !
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OpenStudy (anonymous):
have u ever encountered this
d (u/v) / dx= { u' v - u v'}/ v^2
where u and v are functions of x
and u' and v' are the derivative of u and v wrt x respectively
OpenStudy (anonymous):
see u have to find the derivative of 4/cotx...right?
OpenStudy (anonymous):
and u know the formula for the derivative of cotx?
OpenStudy (anonymous):
i.e. d(cot x)/ dx= - cosec^2 x
OpenStudy (anonymous):
and u r using this in finding out the derivative of 1/ cotx
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OpenStudy (anonymous):
so why i asked u...d(1/x)/ x= ?
OpenStudy (anonymous):
it should be 1 because the derivative of x is 1 so d(1/x)/ dx=1
OpenStudy (anonymous):
the derivative of x is 1
so d(1/x)/ dx=1
OpenStudy (anonymous):
u agree that derivative of 1/x is -1/x^2
but how did it come?