Question

Solve by elmination/ substitution

4x-2y+5z=6
3x+3y+8z=4
x-5y-3z=5

Answer 1

Do you solve for x using the third equation?

Answer 2

you can then put that answer for x into both of the first two equations and then solve for y or z then put your answer back into the original equations

Answer 3

this works out good
so
you get x=5y+3z+5
so now sub for x in other two equations and substract those two equations and the y 's cancell and that gives you z and the go backwards.

Answer 4

Wouldn't the z cross out too?
4(5y+3z=5)-2y+5z=6
20y+12z+20-2y+5z+6
18y+17z+20=6
18y+17z=-14

3(5y+3z+5)+3y+8z=4
15y+9z+15+3y+8z=4
18y+17z+15=4
18y+17z=-11

Answer 5

yes let me look at something

Answer 6

so there is no solutions

Answer 7

Thank you very much. :)