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Mathematics 12 Online
OpenStudy (anonymous):

y

OpenStudy (goformit100):

diffrentiate both side w.r.t.x.

OpenStudy (anonymous):

-2xe^-x^2

OpenStudy (anonymous):

@goformit100 so how do i find the interval at which f(x) is cancave downward and upward

OpenStudy (zarkon):

you need to find the second derivative

OpenStudy (anonymous):

(-2e^-x^2)+4x^2(e^-x^2)

OpenStudy (zarkon):

find where the second derivative is zero

OpenStudy (anonymous):

1/2sqrt(2)

OpenStudy (anonymous):

-1/2SQRT(2)

OpenStudy (zarkon):

your two numbers break the number line into 3 intervals. Pick a number form each of the intervals and plug into the second derivative and note whether it is a positive or negative number

OpenStudy (zarkon):

positive means concave up...negative means concave down

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