Question

Write an equation of a line in slope intercept form that is perpendicular to y = -4x -2 and passes through the point (-16, -11).

Write an equation of a line in slope intercept form that is parallel to the line x + 4y = 6 and passes through (-8, 5).

Write an equation of a line in slope intercept form that is perpendicular to the line 2x -3y = 12 and passes through the point (2, 6).

Answer 1

ok few things u need to know.. when lines are parallel, they have the same slope..
and when one line is perpendicular to other line their slpe have this relation :
m1*m2 = -1

Answer 2

Alright! I know how to do them, but these are the last 3 questions to my study guide, I've been doing it for about two hours. If you could solve them I would be so grateful. Thanks! :)

Answer 3

well first it's a learning site not a solution site.. everyone can walk you through the questions..
for 1st question..
can u tell me what will be the slope of the equation u have to find?

Answer 4

nubeer is correct....you need to determine the slope of the required line first...for that as u can understand u must bring the eqn of the given line to y=mx+c form....now notice if the required line is parellel or perp to the given line...then do as nubeer said and determine the slope...now slope =(y-Y)?(x-X)...where Y,X are the co-ords of the givn point through which the reqd line passes...
q1:
clearly slope of the given line=-4
slope of reqd line then...=1/4( note they r perp)
line passes through (-16,-11)
then eqn..:
1/4=(y-(-11))/(x-(-16))
thats x-4y=18
Q2:
given line:
x+4y=6
thats y=-x/4+6/4
this is the slope intercept form of the GIVEN line
then slope of given line=-1/4
now slope of reqd line =-1/4( note they r parrellel)
line passes thru(-8,5)
eqn of reqd line:
-1/4=(y-5)/(x-(-8))
thats x+4y=12
are these two ans correct...then u can do the thrd one...its the same as the first