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Mathematics 13 Online
OpenStudy (well):

Hello, we have : (1/x) + x < 2 (1/x) + x = 2 /*x 1 + x^2 = 2x x^2 - 2x + 1 = 0 (x-1)^2 = 0 x = 1 x < 1 Is this correct ? Becuause wolfram said result is x < 0 ?!

OpenStudy (nubeer):

i think its right..

OpenStudy (well):

I will w8 few minutes if somebody else will find mistake. If not will close it with correct answer x < 1

OpenStudy (amriju):

whats the second line...?

OpenStudy (well):

linear equation ? just put "=" in place of "<"

OpenStudy (well):

of course i can count with "<" but "=" looks more naturally when you solve equation

OpenStudy (amriju):

k.... (1/x+x)<=|2|...was not that the condition

OpenStudy (well):

I dont understand you amriju ..

hartnn (hartnn):

u cannot solve it like that, u need to consider < sign only

hartnn (hartnn):

(1/x) + x < 2 Let x>0 , u got (x-1)^2 < 0 which is not possible because a square of a number is always positive hence x<0

hartnn (hartnn):

only when x>0, u multiply x on both sides, and u don't flip the sign

OpenStudy (well):

It is not clear to me at all..

hartnn (hartnn):

consider when x<0 so when u multiply x on both sides, u should flip the sign and u get (x-1)^2 > 0 which confirms x<0

OpenStudy (well):

Thanks a lot. But i still dont understand where i put mistake and how i should solve it. I dont understan english at all. I just need time to understand it

hartnn (hartnn):

Did u know that u should flip the inequality sign when multiplying or dividing by a negative number ? ex. if x>0, -x <0 Your mistake, u cannot just replace < with = and replace it back after solving it.....

hartnn (hartnn):

will it help if i put all steps together ?

OpenStudy (well):

I just know.. that if i multiply it by -1 for example.. i flip the sign of course..

OpenStudy (well):

but i just multiply it by x to get 1 + x^2 = 2x

OpenStudy (well):

Dont know if you are pointing on this step or not..

hartnn (hartnn):

yeah, we don't know whether x is positive or negative. if positive, we need not flip the sign, if negative, we need to flip the sign. hence, we go for 2 conditions.

OpenStudy (well):

Ah ok.. i understand now..

OpenStudy (well):

but how this affect that result is x < 0 ? Iam so dumb.. sorry

hartnn (hartnn):

(1/x) + x < 2 consider (i) x>0 (ii) x<0 u get (x-1)^2 < 0 u get (x-1)^2 < 0 NEVER true, Always true so x is not greater than 0. hence the inequality (1/x) + x < 2 is satisfied for all x<0 hence x<0 is solution

OpenStudy (well):

Ah, now i understand it. Thanks a lot for detailed description.. ;)

hartnn (hartnn):

welcome ^_^

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