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Mathematics 16 Online
OpenStudy (anonymous):

Solve, using the substitution method. y – 2x = 8 16 + 4x = 2y

Parth (parthkohli):

Isolate \(\rm \large y\) in the first equation to start with.

OpenStudy (anonymous):

im confused idk how to do anything

Parth (parthkohli):

Google how to use the substitution method.

OpenStudy (anonymous):

i did and i dont understand

Parth (parthkohli):

Do you want an example?

OpenStudy (anonymous):

ok yeah

OpenStudy (anonymous):

2x-y=16 -x+2y=-8

Parth (parthkohli):

For example, you have this:\[\rm y - 2 = x \\ 3y +1 = 4x -7\]First, you have to find what \(\rm \large y\) equals in terms of \(\rm x\). You can write the first equation as \(\rm \large y = x + 2\)

OpenStudy (anonymous):

tthat was the equation im trying to get an answer to

Parth (parthkohli):

Since \(\large\rm y = x + 2 \), you can write the second equation as\[\rm \large 3(x + 2) + 1 = 4x - 7\]

OpenStudy (anonymous):

where did u get 4 from ?

Parth (parthkohli):

It's my sample equation.

OpenStudy (hba):

@shscheer Did You Get It ?

OpenStudy (anonymous):

no but is it like this 2x-y=16 -x+2y=-8 -4x+2y=-16 4x-2=16 -4x+2y=-16 4x-2y=16 0,0?

OpenStudy (hba):

Lets Start Over :)

OpenStudy (anonymous):

ok :)

OpenStudy (hba):

Solve, using the substitution method. 2x – 3y = –2 4x + y = 24

OpenStudy (hba):

^^ We Are Going To Use This as a sample question to understand :)

OpenStudy (anonymous):

se i dont know how to do any of this i need someone to go step by stepwith me

OpenStudy (hba):

Well I Am Gonna Go Step By Step Dont Worry

OpenStudy (hba):

|dw:1350836362700:dw|

OpenStudy (hba):

The idea here is to solve one of the equations for one of the variables, and plug this into the other equation. It does not matter which equation you pick first

OpenStudy (hba):

|dw:1350836485708:dw|

OpenStudy (hba):

Do You Get it till here

OpenStudy (hba):

@shscheer

OpenStudy (anonymous):

yes because u plugged in the numbers for the variables right?

OpenStudy (hba):

|dw:1350836630285:dw|

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