Solve, using the substitution method. y – 2x = 8 16 + 4x = 2y
Isolate \(\rm \large y\) in the first equation to start with.
im confused idk how to do anything
Google how to use the substitution method.
i did and i dont understand
Do you want an example?
ok yeah
2x-y=16 -x+2y=-8
For example, you have this:\[\rm y - 2 = x \\ 3y +1 = 4x -7\]First, you have to find what \(\rm \large y\) equals in terms of \(\rm x\). You can write the first equation as \(\rm \large y = x + 2\)
tthat was the equation im trying to get an answer to
Since \(\large\rm y = x + 2 \), you can write the second equation as\[\rm \large 3(x + 2) + 1 = 4x - 7\]
where did u get 4 from ?
It's my sample equation.
@shscheer Did You Get It ?
no but is it like this 2x-y=16 -x+2y=-8 -4x+2y=-16 4x-2=16 -4x+2y=-16 4x-2y=16 0,0?
Lets Start Over :)
ok :)
Solve, using the substitution method. 2x – 3y = –2 4x + y = 24
^^ We Are Going To Use This as a sample question to understand :)
se i dont know how to do any of this i need someone to go step by stepwith me
Well I Am Gonna Go Step By Step Dont Worry
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The idea here is to solve one of the equations for one of the variables, and plug this into the other equation. It does not matter which equation you pick first
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Do You Get it till here
@shscheer
yes because u plugged in the numbers for the variables right?
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