Question

n nmbm,

Answer 1

well 1st off you are looking at a 1st quadrant graph given the condition for x and y

slope- intercept form is y = mx + b

or for the inequalities

2x + y <= 14

subtract 2x from both sides

y<= 14 - 2x

similar process for

2x + 5y >= 35

with an extra step of dividing each term by 5

lastly

P = 3x + 2y

similar again

2nd step is divide by 2

Answer 2

thats correct...

a similar process for the P equation.

Answer 3

ok... so you are looking to solve simultaneously to get the point of intersection

3x + 5y = 35
2x + y = 14

or since you have both in slope intercept form you can say

-2x + 14 = -3/5x + 5

and solve for x... the find the y value by substituting into either equation.

Answer 4

I just used a graphing package you don't need to point of intersection you just need to find the x and y intercepts for each line.

Answer 5

oops my mistake... had the equation the wrong way around.

and your correct.

Answer 6

can you find the x and y intercepts for both lines...?

Answer 7

for 3x+ 5y = 35,
to find x-intercept take y=0
3x+ 5(0) = 35
3x = 35
x= 35/3, so coordinat point at (35/3, 0)
to find y-intercept take x=0
3(0)+ 5y = 35
5y = 35
y= 7, so coordinat point at (0,7)
do same for the line of 2x + y = 14

Answer 8

well isn't your solution graphically