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Does there exist a sum formula of a geometric infinite series?
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the ratio,r should satisfy the following condition for that | r| < 1
Okay, it does.
For example,\[\rm \large{1} + {1 \over 3}+ {1 \over 9} +{ 1 \over 27}\cdots \]
formulla is a/(1-r) where a and r have their usual meanings..
U mean sum formula?
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yes.
\[\large \rm {1 - r^n \over 1 - r}\]So, how to derive that ^^ formula from this one?
I mean, how to derive\[\large\rm {a\over 1 - r}\]from the usual formula given above?
since |r| < 1 and n tends to infinity,, hope you can verify r^n --> 0
Yes... a limit... yes.
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and that gives us our simplified form/ans..
Oh! That was very easy. lol
Oops, yes.
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