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Find dy/dx of (1+cos^2 7x)^3
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chain rule for this one
\[\frac{d}{dx}(1+\cos^2(7x))^3=3(1+\cos^2(7x))^2\times (2\cos(7x))\times (-\sin(7x))\times 7\]clean up with algebra
So, How do you find d/dx of cos^2(x)? I can't quite remember if it is just 2cos(x), or if you have to do something special to it.
chain rule first take care of the square, then take care of the cosine
the derivative of \(f^2(x)\) is \(2f(x)f'(x)\)
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So, it will become 2cos(x), then become -2sin(x)?
no the derivative of some function squared is two time that function, times the derivative of that function more succinctly written as \[(f^2)'=2ff'\]
So you use the product rule?
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