Question

Calculus: The Comparison Test

I'm supposed to show if convergent or divergent using the comparison test or limit comparison test:

(n-1)!/(n+2)!

Answer 1

use limit comparison test and then u can show that this series is convergent.

Answer 2

u know limit comparison test?

Answer 3

or u can show using comparison test also.

Answer 4

(n-1)!/(n+2)! = 1/n(n+1)(n+2) ---a(n)
look for some other series---b(n) about which u know that either it's convergent or divergent
suppose b(n)= 1/n^3 and this is convergent .
a(n) and b(n) are +ve for all n.
a(n)< b(n)
since b(n) is convergent so a(n) will also converge.

Answer 5

does it help u?

Answer 6

Yes! Thanks!

Answer 7

:)