Question

why does n!/(n+1)!=1/(n+1)?

Answer 1

it doesnt?

Answer 2

My calculus book says tit does :(

Answer 3

n!/(n+1)!=1/(n+1)

n!/[(n+1)n!]=1/(n+1)

1/(n+1)=1/(n+1)

Answer 4

So (n+1)!=(n+1)n!?

Answer 5

I cant find any "rules" of factorials online

Answer 6

yes, this is because

n! = n*(n-1)*(n-2)...3*2*1

so

(n+1)! = (n+1)*n*(n-1)*(n-2)...3*2*1

(n+1)! = (n+1)*[ n*(n-1)*(n-2)...3*2*1 ]

(n+1)! = (n+1)*[ n! ]

(n+1)! = (n+1)*n!