Question

can somebody please help me on this problem, i am not sure how to work out this problem since it has fractions in it, i have to figure out if it is no solution or no identity

Answer 1

\[\frac{ 1 }{ 7 }\left( 14-7p \right)-2=-2 (\frac{ 1 }{ 2 }p+3)+6\]

Answer 2

If you distribute, the fractions will go away

\[\Large \frac{ 1 }{ 7 }\left( 14-7p \right)-2=-2 (\frac{ 1 }{ 2 }p+3)+6\]

\[\Large \frac{ 1 }{ 7 }*14+\frac{ 1 }{ 7 }(-7p)-2=-2*\frac{ 1 }{ 2 }p-2*3+6\]

\[\Large \frac{ 14 }{ 7 }+\frac{ -7p }{ 7 }-2=\frac{ -2 }{ 2 }p-6+6\]

\[\Large 2-p-2=-p-6+6\]

I'll let you finish

Answer 3

thanks

Answer 4

yw