OpenStudy (anonymous):

multiply binomial (a+2)^3

OpenStudy (anonymous):

first seperate it out

OpenStudy (anonymous):

(a+2)(a+2)(a+2)

OpenStudy (anonymous):

then multiply the first 2 blobs

OpenStudy (anonymous):

so then it becomes (a^2+4a+4)(a+2)

OpenStudy (anonymous):

so this is what I did a^3+a^2+2 is this correct no it is not correct

OpenStudy (anonymous):

no the right answer is \[a ^{3}+6a ^{2}+12a+8\]