Question

I'm having trouble understanding how to differentiate sinxtanx. Can someone please help me?

Answer 1

For this we need the product rule

Answer 2

Im stuck after secxsec(^2)x+tanx(secx+tanx)

Answer 3

what is the derivative of sin(x)?

Answer 4

cosx

Answer 5

and the derivative of tan(x)?

Answer 6

right, so if y= sin(x)*tan(x),
then y' = (sin(x))'(tan(x)) + sin(x)(tan(x))'

Answer 7

\[\sec ^{2}x\]

Answer 8

good, so now that you know how to differentiate both terms, you can do this

y' = (sin(x))'(tan(x)) + sin(x)(tan(x))' = ???

Answer 9

I'm not sure how my solutions manual got secx(1+2tan(^2)x) though

Answer 10

OHH wait. I got it. Thank you! I overlooked a couple steps.

Answer 11

good job, please leave me a medal and fan :D