Ask your own question, for FREE!
Chemistry 13 Online
OpenStudy (anonymous):

highschool chemistry question?

OpenStudy (anonymous):

For the following reaction, identify the element that was oxidized, the element that was reduced, and the reducing agent. Give an explanation for each answer. SnCl2 + PbCl4 --> SnCl4 + PbCl2

OpenStudy (anonymous):

Reduction is the gain of electrons or a decrease in oxidation state by a molecule, atom, or ion yes?

OpenStudy (anonymous):

correct @HyperChemist

OpenStudy (australopithecus):

SnCl2 + PbCl4 --> SnCl4 + PbCl2 SnCl2 has an oxidation state of +2 SnCl4 has an oxidation state of +4 PbCl4 has an oxidation state of +4 PbCl2 has an oxidation state of +2 SnCl2 + 2e- = SnCl4 PbCl4 -> PbCl2 + 2e-

OpenStudy (australopithecus):

Remember reduction is the acceptance of electrons Oxidation is the loss of electrons

OpenStudy (australopithecus):

Thus the oxidating agent would be the one donating the electrons

OpenStudy (australopithecus):

Oxidation state is the charge atoms would have if every bond was a 100% ionic

OpenStudy (australopithecus):

|dw:1351045442690:dw|

OpenStudy (anonymous):

cl-, sn+2, cl-.......

OpenStudy (australopithecus):

It is a good idea to write reactions like this into two reactions to determine which is getting the electrons and what is donating the electrons

OpenStudy (anonymous):

does this mean that cl lost 2 electrons? and that sn gained two?

OpenStudy (australopithecus):

the Sn would have to gain 2 electrons in order to bond to 4Cl, I believe

OpenStudy (anonymous):

Ok, I see.....may I please ask why you wrote it like sn-?

OpenStudy (australopithecus):

sn-?

OpenStudy (anonymous):

ooh...nvm, I see...

OpenStudy (anonymous):

may I also write why you wrote it in two parts rather than 2sn-?

OpenStudy (anonymous):

Oh, I mean, Cl-2.

OpenStudy (australopithecus):

yeah I made a mistake :)

OpenStudy (anonymous):

oh man whats wrong with me today...sorry...

OpenStudy (anonymous):

oh really? hmmm, explain please.

OpenStudy (australopithecus):

Sn+2 + 2e- -> Sn+4 Pb+4 -> Pb+2 + 2e-

OpenStudy (australopithecus):

I dont think I should have included the ligands

OpenStudy (australopithecus):

or chlorine rather

OpenStudy (anonymous):

ok then, 2e- is the number of electrons lost? and in the produce is gained?

OpenStudy (anonymous):

also down...Pb+4-=pb+ 2e-....

OpenStudy (australopithecus):

Sn is reduced and gains two electrons and thus increasing the chlorine ligands from 2 to 4 Pb is oxidized and loses 2 electrons reducing its chlorine ligands to 2

OpenStudy (australopithecus):

Sn is the oxidizing agent because it removes electrons from Pb

OpenStudy (anonymous):

I think I can clearly see this now...you just taught me a whole day of school sir, I actually never seen this before, thank you very much for showing me this, I have a better understanding now.

OpenStudy (anonymous):

have a nice night.

OpenStudy (australopithecus):

No problem yeah this stuff always seemed fuzzy to me until I explained it to you

OpenStudy (anonymous):

Sorry - I had fell asleep last night. But anyways, thanks for discussing this all on my question, I understand it pretty well now. :)

OpenStudy (preetha):

Australopithecus, really nice explanation. Well done!

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!