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OpenStudy (anonymous):
Theorem says :
\[tangent^2 = Secant \cdot Chord\]
OpenStudy (anonymous):
I.e :
\[AB^2 = AD \cdot AC\]
Just plug in the values..
jimthompson5910 (jim_thompson5910):
according to theorem 3 on that page
b*c = a^2
In this context, if AB = x, AD = 8 and AC = 24.5, then
(AD)*(AC) = (AB)^2
8*24.5 = x^2
Keep going to solve for x
OpenStudy (anonymous):
38416 . that is what i got cause i did 8*24.5 which equals 196 , then 196^2 and that gives me 38416 .
jimthompson5910 (jim_thompson5910):
you take the square root of 196
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