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Geometry 18 Online
OpenStudy (anonymous):

can someone help me please ? If AD = 8 cm and AC = 24.5 cm, calculate the length of AB. A. 16 cm B. 15 cm C. 30.63 cm D. 14 cm

OpenStudy (anonymous):

OpenStudy (anonymous):

do you know this ?

jimthompson5910 (jim_thompson5910):

hint: use theorem 3 on this page http://www.regentsprep.org/Regents/math/geometry/GP14/CircleSegments.htm

OpenStudy (anonymous):

Liked it..

OpenStudy (anonymous):

i just still don't get this .

OpenStudy (anonymous):

Theorem says : \[tangent^2 = Secant \cdot Chord\]

OpenStudy (anonymous):

I.e : \[AB^2 = AD \cdot AC\] Just plug in the values..

jimthompson5910 (jim_thompson5910):

according to theorem 3 on that page b*c = a^2 In this context, if AB = x, AD = 8 and AC = 24.5, then (AD)*(AC) = (AB)^2 8*24.5 = x^2 Keep going to solve for x

OpenStudy (anonymous):

38416 . that is what i got cause i did 8*24.5 which equals 196 , then 196^2 and that gives me 38416 .

jimthompson5910 (jim_thompson5910):

you take the square root of 196

jimthompson5910 (jim_thompson5910):

this will give you a smaller number (than 196)

OpenStudy (anonymous):

14 !!

OpenStudy (anonymous):

thanks for helping me out on this (: i was lost !

jimthompson5910 (jim_thompson5910):

yw

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