Question

Calculus: Find the derivative.
y=x^3cosx

Answer 1

\[x ^{3}\cos x\]

Answer 2

product rule \[(f(x)g(x))^{\prime}=f^{\prime}(x)g(x)+f(x)g^{\prime}(x)\]

Answer 3

can u explain more pls? xD

Answer 4

like how to do it cause i dont get it :\

Answer 5

\[f(x)=x^3;g(x)=\cos{x};\;\;
[f(x)g(x)]^{\prime} = (x^3)^{\prime}\cos{x}+x^3(\cos{x})^{\prime}\]

Answer 6

Do you not understand how to do the actual derivatives or the product rule?

Answer 7

I just dont know how to do this problem :)

Answer 8

\[(x^3)^{\prime} = 3x^{(3-1)}\] from the power rule
\[(\cos{x})^{\prime} = -\sin{x}\]
\[3x^2\cos{x}-x^3\sin{x}\]