Mathematics
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OpenStudy (anonymous):
How to get the right side ?
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OpenStudy (anonymous):
OpenStudy (goformit100):
its easy, take inequality in use
OpenStudy (lgbasallote):
there was once a famous quote..."one must go left to turn right"
OpenStudy (anonymous):
I know how to get the left side but I am having a hard time to get the right one :)
OpenStudy (lgbasallote):
this is proving yes?
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OpenStudy (anonymous):
no , i am trying to solve a fourier series of sawtooth function. and this bn coefficient
OpenStudy (lgbasallote):
hmm interesting
OpenStudy (lgbasallote):
i believe this is @hartnn 's specialty yes?
OpenStudy (anonymous):
I am new i do not know nobody in here :(
hartnn (hartnn):
speciality ? no.
M7, what is cos pi = ?
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hartnn (hartnn):
what is cos pi ?
OpenStudy (anonymous):
cos pi ? it's -1 ..
hartnn (hartnn):
and cos 2pi = ?
OpenStudy (anonymous):
one
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hartnn (hartnn):
cos 3pi = ?
OpenStudy (anonymous):
:) .. well what is your point ?
hartnn (hartnn):
see the pattern ....
cos n*pi = ?
hartnn (hartnn):
cos 1pi = -1
cos 2pi = 1
cos 3pi = -1
cos 4pi = 1
OpenStudy (anonymous):
yeah i see it's 1,-1,1 and so on
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hartnn (hartnn):
so cos n*pi= ?
OpenStudy (anonymous):
Under which topic in math can i find such examples ..
hartnn (hartnn):
just use generalization :
cos n*pi = \(\huge (-1)^n\)
hartnn (hartnn):
when i put 1, i get -1, when i put n=2, i get +1 and so o n
OpenStudy (anonymous):
Awesome
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hartnn (hartnn):
and -cos (n*pi) = (-1)(-1)^n = ?
hartnn (hartnn):
and i think sin n*pi will be easier for you to figure out
OpenStudy (anonymous):
Hartnn thank you so much, you saved my life :)
hartnn (hartnn):
welcome ^_^