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Mathematics 19 Online
OpenStudy (anonymous):

How to get the right side ?

OpenStudy (anonymous):

OpenStudy (goformit100):

its easy, take inequality in use

OpenStudy (lgbasallote):

there was once a famous quote..."one must go left to turn right"

OpenStudy (anonymous):

I know how to get the left side but I am having a hard time to get the right one :)

OpenStudy (lgbasallote):

this is proving yes?

OpenStudy (anonymous):

no , i am trying to solve a fourier series of sawtooth function. and this bn coefficient

OpenStudy (lgbasallote):

hmm interesting

OpenStudy (lgbasallote):

i believe this is @hartnn 's specialty yes?

OpenStudy (anonymous):

I am new i do not know nobody in here :(

hartnn (hartnn):

speciality ? no. M7, what is cos pi = ?

OpenStudy (anonymous):

just have a look to this example in wikibidia http://en.wikipedia.org/wiki/Fourier_series

hartnn (hartnn):

what is cos pi ?

OpenStudy (anonymous):

cos pi ? it's -1 ..

hartnn (hartnn):

and cos 2pi = ?

OpenStudy (anonymous):

one

hartnn (hartnn):

cos 3pi = ?

OpenStudy (anonymous):

:) .. well what is your point ?

hartnn (hartnn):

see the pattern .... cos n*pi = ?

hartnn (hartnn):

cos 1pi = -1 cos 2pi = 1 cos 3pi = -1 cos 4pi = 1

OpenStudy (anonymous):

yeah i see it's 1,-1,1 and so on

hartnn (hartnn):

so cos n*pi= ?

OpenStudy (anonymous):

Under which topic in math can i find such examples ..

hartnn (hartnn):

just use generalization : cos n*pi = \(\huge (-1)^n\)

hartnn (hartnn):

when i put 1, i get -1, when i put n=2, i get +1 and so o n

OpenStudy (anonymous):

Awesome

hartnn (hartnn):

and -cos (n*pi) = (-1)(-1)^n = ?

hartnn (hartnn):

and i think sin n*pi will be easier for you to figure out

OpenStudy (anonymous):

Hartnn thank you so much, you saved my life :)

hartnn (hartnn):

welcome ^_^

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