Anyone who can help me rewrite the set for a function?

Question

frostbite · Answer

a function f is given by f(x,y)=x+y^2, {(x,y)∈R^2 | 0<= x <= 2, x-2<=y<=x}

frostbite · Answer

I want it rewrited to the form:
{(x_1,…,x_n ) | f1 (x_1,…,x_n)≥a_1,…,f_k (x1,…,xn )≥a_k },

frostbite · Answer

see attachment if it is

anonymous · Answer

Well, f_1 is x >=y   and  

f_2 is y >= x-2 >= -2

frostbite · Answer

Well f2 have to be seperated with the use of a Intersection. but that is where i become unsure

anonymous · Answer

i am confused. 
is your answer supposed to look something like 
$$\{(x,y):x+y^2>a_1, x+y^2>a_2\}$$?

frostbite · Answer

I think i am going to show that the set i have shown can be rewitten so that a function consisting of x and/or y >= than a number called a.

anonymous · Answer

frostbite · Answer

Sure do if you look at the alternative form you can just make a minor a rewirteing of that and bam you get what i want. Thanks.

anonymous · Answer

yw:-)

frostbite · Answer

ok: fast question: they show the logical operator and (∧) but can i switch that out with the intersection (∩)?

frostbite · Answer

Should kinda be the same in my eyes in this case?

anonymous · Answer

x in A intersects B  iff  x in A  and  x in B  is the definition of set intersection