HELP! Find a line that goes through (1,-6) and is parallel to the line of x+2y=6

Question

0bucchr · Answer

gradient = -0.5
y = mx + c
-6 = (-0.5)*(1) + c
c = -5.5
y = -0.5x - 5.5

anonymous · Answer

1) find the parallel slope you need: 
     x+2y=6; so 2y=-x+6; so y=-(1/2)x+3
    so the slope is -(1/2)
2) find a line that goes through (1,-6) with a slope of -(1/2)
$$y=-\frac{1}{2}x+b$$
$$-6=-\frac{1}{2}(1) + b$$
$$-6+\frac{1}{2} =b$$ 
Therefore the line is $$y=-\frac{1}{2}x -\frac{11}{2}$$

anonymous · Answer

in my textbook it says that the answer is x+2y+11=0. I just dont understand how to get that

anonymous · Answer

Thats the same thing. Multiply my whole equation by 2 you get
$$2y=-x-11$$ 
add x+11 to both sides gives 
x+2y+11-0

anonymous · Answer

Sorry gives 
x+2y+11=0

anonymous · Answer

oh wow. that was simple lol. thank you for the help :)