that was what you used to get the answer to number 4
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OpenStudy (anonymous):
Ari, srry, im having trouble with number 2
OpenStudy (anonymous):
o
OpenStudy (aripotta):
ok
OpenStudy (anonymous):
tnx:)
OpenStudy (aripotta):
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OpenStudy (anonymous):
Ari, the one you just hlped me on, was that the one withbthencoordinate points listed or the one about george?
OpenStudy (aripotta):
so the hypotenuse is 17...do you see how i got the the lenght of the one leg?
OpenStudy (anonymous):
and tnx
OpenStudy (aripotta):
with the coordinates listed
OpenStudy (anonymous):
tnx,let me look at ur most recent snapshot
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OpenStudy (anonymous):
ok.mcan you explain what x is?
OpenStudy (aripotta):
yea, i was just asking you if you knew how i got 15 for the length of the one side? because if you know this, you can basically do any question similar to this
OpenStudy (anonymous):
oh.no. how?
OpenStudy (aripotta):
did you notice how the area of that square was 225? how can we find the side length of a square?
OpenStudy (anonymous):
sq root oof area
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OpenStudy (aripotta):
yep, and that's how we got 15, does that make sense?
OpenStudy (anonymous):
15
OpenStudy (anonymous):
yes,ma'am
OpenStudy (aripotta):
so if we know the hypotenuse is 17, and a leg is 15...how can we go about finding the other leg length?
OpenStudy (anonymous):
15+x=17?
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OpenStudy (aripotta):
what's the Pythagorean theorem?
OpenStudy (anonymous):
a^2+b^2=c^2
OpenStudy (anonymous):
15^2+b^2=17^2?
OpenStudy (aripotta):
yep
OpenStudy (anonymous):
yay
so i solve?
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OpenStudy (aripotta):
if you know how to. show me what you think you do
OpenStudy (anonymous):
3.8-4.1
OpenStudy (aripotta):
you're doing the square root again!
OpenStudy (anonymous):
ii mean the other way around
OpenStudy (aripotta):
don't! lol
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