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sqrt (2x -3= 5 ) Solve for x?
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\[\sqrt{2x-3}=5\]?
yes
if so, square both sides and get \[2x-3=25\] then solve that one in two steps
I just basically need to understand how to do these kind of questions
add 3, divide by 2
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if you have a square root, you need to get rid of it by squaring both sides of the equation
okay and when you square it, it just stays the same. correct?
because its already rooted?
when you square it, the square root is gone
ok
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