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Mathematics 19 Online
OpenStudy (anonymous):

find the critical numbers of f if any and locate all relative extrema. f(x)=x/x+1

OpenStudy (anonymous):

Critical points are just points in f(x) when f'(x) = 0, basically you are finding the roots of the derivative and plugging the x values back into your function. What's in your way? Do you know how to take a derivative? Do you know how to find roots?

OpenStudy (anonymous):

i know how to find the derivative i just get stuck on finding the roots for this problem

OpenStudy (anonymous):

Okay, what is your derivative?

OpenStudy (anonymous):

i got 1/(x+1)^2

OpenStudy (anonymous):

Okay so we have:\[\frac{1}{(x+1)^2}=0\]Make sense?

OpenStudy (anonymous):

yeas

OpenStudy (anonymous):

Okay, so first we can multiply both sides by \((x+1)^2\).

OpenStudy (anonymous):

What you get?

OpenStudy (anonymous):

u mean multiply (x+1)^2 on both sides of the equation?

OpenStudy (anonymous):

wait... right that doesn't work does it...

OpenStudy (anonymous):

nope

OpenStudy (anonymous):

Well we might now have any roots...

OpenStudy (anonymous):

not have any?

OpenStudy (anonymous):

yeah, looks like there aren't any... since you can't get the left hand side to be 0.

OpenStudy (anonymous):

okay so then how do i proceed w. this problem?

OpenStudy (anonymous):

Well, it seems like there are no critical points, so I would assume there are no relative extrema

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