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What is the standard form equation of the line passing through (3, -2) with a slope of 3/5 ? 5x - 3y = 19 5x - 3y = -19 3x - 5y = 19 3x - 5y = -19
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Hello
Yah there?
can you answer this question^
Ok so we know the form y=mx+b where y and x are you interval values and x is you slope
yes
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m is your slope i mean
so lets plug them in
-2=3/5(3)+b right
yes
y=-2 x=3 m= 3/5
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Then we solve for b
we find b = 3.8
plug b into our equation giving us y=3/5x+3.8
multiply both sides by 5 giving us 5y=3x+19
subtract 3x over giving 5y-3x=19
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that is the same as 3x-5y=-19
i believe that is one of your answers
good?
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