1. Suppose you take a true/false quiz that contains five true/false questions. Let an even digit represent a correct answer and an odd digit represent an incorrect answer. In the five trials shown, how often did you get at least 3 questions correct? (Note: Assume there is a 0 before the number 4908 in the first trial.)
You need to give the five numbers for the 5 trials to enable anybody to help you.
4908 98427 57497 90707 28507
@kropot72
Do you know whether zero is even or odd?
RanIt, 0,99999
It's even right
Yes, zero is an even number. How many even digits are there in the first number?
4?
Good, you're right. So you can now finish the problem?
Uhhhh.... So 4 is the answer
No! It's 3!!!
Right!????
No, 4 is not the final answer. The result of finding 4 even digits in the first number means that in the first trial 3 or more questions were answered correctly. The second number is the result of the second trial. Were 3 or more questions answered correctly in the second trial?
It's 3
Is 3 your answer to the question "how often did you get at least 3 questions correct?"
Yes 3 is my final answer
The correct answer is that you got 3 or more questions right in 3 out of 5 trials.
So yes 3 is correct
Not really. The question asks "how often" therefore your answer must include "3 out of 5 trials"
Ok
Glad that you understand :)
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