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Mathematics 18 Online
OpenStudy (anonymous):

1. Suppose you take a true/false quiz that contains five true/false questions. Let an even digit represent a correct answer and an odd digit represent an incorrect answer. In the five trials shown, how often did you get at least 3 questions correct? (Note: Assume there is a 0 before the number 4908 in the first trial.)

OpenStudy (kropot72):

You need to give the five numbers for the 5 trials to enable anybody to help you.

OpenStudy (anonymous):

4908 98427 57497 90707 28507

OpenStudy (anonymous):

@kropot72

OpenStudy (kropot72):

Do you know whether zero is even or odd?

OpenStudy (anonymous):

RanIt, 0,99999

OpenStudy (anonymous):

It's even right

OpenStudy (kropot72):

Yes, zero is an even number. How many even digits are there in the first number?

OpenStudy (anonymous):

4?

OpenStudy (kropot72):

Good, you're right. So you can now finish the problem?

OpenStudy (anonymous):

Uhhhh.... So 4 is the answer

OpenStudy (anonymous):

No! It's 3!!!

OpenStudy (anonymous):

Right!????

OpenStudy (kropot72):

No, 4 is not the final answer. The result of finding 4 even digits in the first number means that in the first trial 3 or more questions were answered correctly. The second number is the result of the second trial. Were 3 or more questions answered correctly in the second trial?

OpenStudy (anonymous):

It's 3

OpenStudy (kropot72):

Is 3 your answer to the question "how often did you get at least 3 questions correct?"

OpenStudy (anonymous):

Yes 3 is my final answer

OpenStudy (kropot72):

The correct answer is that you got 3 or more questions right in 3 out of 5 trials.

OpenStudy (anonymous):

So yes 3 is correct

OpenStudy (kropot72):

Not really. The question asks "how often" therefore your answer must include "3 out of 5 trials"

OpenStudy (anonymous):

Ok

OpenStudy (kropot72):

Glad that you understand :)

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